When is a z-test appropriate for testing a population mean?

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Multiple Choice

When is a z-test appropriate for testing a population mean?

Explanation:
Z-testing a population mean relies on knowing the population standard deviation and on the sampling distribution of the sample mean being normal. When sigma is known, the test statistic uses sigma in the denominator: Z = (X̄ − μ0) / (σ/√n). This follows a standard normal distribution under the null hypothesis if the population is normal or if the sample size is large enough for the Central Limit Theorem to make the sampling distribution of the mean approximately normal. That combination—known sigma plus a normal/population-wide normality or a large n—is what makes a z-test appropriate. If sigma is unknown, you’d use a t-test with the sample standard deviation and the t distribution, and with categorical data a z-test for a mean isn’t applicable.

Z-testing a population mean relies on knowing the population standard deviation and on the sampling distribution of the sample mean being normal. When sigma is known, the test statistic uses sigma in the denominator: Z = (X̄ − μ0) / (σ/√n). This follows a standard normal distribution under the null hypothesis if the population is normal or if the sample size is large enough for the Central Limit Theorem to make the sampling distribution of the mean approximately normal. That combination—known sigma plus a normal/population-wide normality or a large n—is what makes a z-test appropriate. If sigma is unknown, you’d use a t-test with the sample standard deviation and the t distribution, and with categorical data a z-test for a mean isn’t applicable.

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